Class 10 Electricity Ncert Solutions May 2026

(a) I²R (b) IR² (c) VI (d) V²/R Answer: (b) IR²

Answer: (i) 9 Ω = two in parallel (3 Ω) + one in series (6 Ω) (ii) 4 Ω = two in series (12 Ω) in parallel with one (6 Ω): ( 1/R = 1/12 + 1/6 = 3/12 ) → R=4 Ω class 10 electricity ncert solutions

Answer: Power ( P = V \times I = 220 \times 5 = 1100 , \text{W} ) Energy = ( P \times t = 1100 \times 2 = 2200 , \text{Wh} = 2.2 , \text{kWh} ) Chapter Exercise Solutions (Page 221–222) Q1. A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R', then the ratio R/R' is: (a) 1/25 (b) 1/5 (c) 5 (d) 25 Answer: Each piece resistance = R/5. Parallel: 1/R' = 5/(R/5) → R' = R/25 → R/R' = 25 → (d) (a) I²R (b) IR² (c) VI (d) V²/R

Answer: ( H = I^2 R t = 5^2 \times 20 \times 30 = 25 \times 20 \times 30 = 15000 , \text{J} ) In-Text Questions (Page 220) Q1. What determines the rate at which energy is delivered by a current? Answer: Electric power ( P = V \times I = I^2 R = V^2 / R ) If the equivalent resistance of this combination is

I’ll provide answers to the and the exercise questions at the end of the chapter. In-Text Questions (Page 200) Q1. What does an electric circuit mean? Answer: An electric circuit is a continuous and closed path for the flow of electric current, consisting of a source of electricity (like a cell or battery), connecting wires, a switch, and a device (like a bulb).