Парсер Datacol Torrent May 2026

# Example usage if __name__ == "__main__": file_path = "path_to_your_torrent_file.torrent" data = parse_torrent(file_path) if data: print(json.dumps(data, indent=4)) The development of a feature to parse datacol torrent files involves careful consideration of what data to extract, how to handle potential errors, and in what format to output the data. By following the outlined steps and example, you can create a robust and useful parser.

def parse_torrent(file_path): try: with open(file_path, 'rb') as f: decoded = bdecode.bdecode(f.read()) info = decoded['info'] # Extracting some key metadata metadata = { 'file_names': [], 'file_sizes': [], 'piece_length': info['piece length'], 'trackers': decoded.get('announce', 'No trackers found'), 'creation_date': decoded.get('creation date', 'No creation date found'), } if 'files' in info: for file in info['files']: metadata['file_names'].append(file['path'][-1]) metadata['file_sizes'].append(file['length']) else: metadata['file_names'].append(info['name']) metadata['file_sizes'].append(info['length']) return metadata except Exception as e: print(f"Error parsing torrent: {e}") return None парсер datacol torrent