X Trench Run Math ((top)) Official

[ P_\texthit \approx 1 - e^-0.913 \approx 1 - 0.401 \approx 0.599 \ (\text59.9%) ]

Assume the torpedo enters the port horizontally at speed (v), then experiences a constant vertical acceleration (a) (from the magnetic field) over a short distance (d) (the shaft length before impact). x trench run math

[ a = \frac2(20)(100^2)10^2 = \frac40 \cdot 10,000100 = 4,000 \ \textm/s^2 \ (\approx 408g) ] [ P_\texthit \approx 1 - e^-0

(h) (depth to target):

That matches the movie’s tension — only a few minutes from “begin your attack run” to firing. The proton torpedoes must turn 90° downward into the exhaust port. But with a magnetic “bend” (in-universe), the real math is a gravity-assisted turn , similar to a ballistic curve. 000100 = 4